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Classifieds > RemoveWAT 2.2.6.zip

RemoveWAT 2.2.6.zip

Posted on 16th June 2022
by hensav
Published: 16th June 2022 (4 years ago)
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RemoveWAT 2.2.6.zip

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RemoveWAT 2.2.6.zip

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Dihydrolipoic acid (DHLA) is a cofactor for the enzyme lipoamide dehydrogenase and thus is involved in the turnover of triacylglycerols, amino acids, and branched-chain amino acids in the cell. For this reason, it has been proposed as a potential regulator of lipoprotein metabolism. We have investigated the effect of DHLA on very low density lipoprotein (VLDL) metabolism and find that it is a potent inhibitor of VLDL apoprotein E synthesis in cell culture. Furthermore, we have developed a novel assay for human VLDL apoprotein E synthesis in which 15N-labeled amino acids are used as substrates. VLDL apoprotein E is produced by incubating cells in media containing 15N-labeled amino acids and then quantifying the amount of VLDL apoprotein E that is 15N-labeled (using a mass spectrometry-based method). Using this method, we demonstrate that DHLA can be used to inhibit VLDL apoprotein E synthesis in a dose-dependent manner. Inhibition occurred without altering the total amount of VLDL apoprotein E in the media. The effect of DHLA was similar to that of cycloheximide, another known inhibitor of protein synthesis. We show that VLDL apoprotein E is synthesized primarily from amino acids present in the cytoplasm (rather than the medium) and is independent of

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Evaluating $ int_{0}^{2}frac{tan(x)}{1+tan^2(x)}, dx$

This task comes from my textbook but I’m unsure how to start:
Evaluate
$$int_{0}^{2}frac{tan(x)}{1+tan^2(x)}, dx$$
Can anybody help me?

A:

HINT
Denoting by $I$ the integral you wish to calculate, $$I=int_{0}^{2}frac{tan x}{1+tan^2x},dx=int_0^1frac{du}{u+tan^2 u}.$$ Then you need to find an antiderivative of the integrand, for instance by means of partial fractions.

A:

let $u = tan x$ then $$int frac{tan x}{1+tan^2x}dx=intfrac{u}{cos^2u+1}du$$ so the antiderivative
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